P
pLuvia
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sqrt{3}-1/sqrt{3}
=(3-1)/sqrt{3}
=2/sqrt{3}
=2sqrt{3}/3
=(3-1)/sqrt{3}
=2/sqrt{3}
=2sqrt{3}/3
Applications of Calc. 2 r.world question (1 Viewer)
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Mc_Meaney
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thanks p
bananasmoothy
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Umm, yeah, sorry for late reply. SoulSearcher is right - I think in a previous part of that same question you had to work out the exact value for k for something, and that's what you use.