Awk moment when I'm stumped on Q4 (Help? :D) (1 Viewer)

[Kanane]

A parabola whose equation is y=ax^2 where a is a constant' has the line y=12x+3 as a tangent.

By using the discriminant of the quadratic equation found, find the value of a


Thanks >_<

 

[anne1010]

equate the two equations. ull get a quadratic. find the discriminant and since they touch one it should equal to 0. then solve for a

 

[jnney]

ax^2 = 12x + 3

ax^2 - 12x - 3 = 0

delta = 144 + 12a

delta = 0 for tangent

144 = -12a

a = -12

 

[Kanane]

Ooh much thanks to both of you haha x]

 

[jnney]

Hehe no problem. Thanks for the rep.

Good luck for hsc!