Balancing (1 Viewer)

[mazza_728]

Why can i not seem to balance these equations?

CH4O+O2 --> CO2+2H20
C3H8O+O2-->CO2+H20
C4H10O+02-->CO2+H2O
C5H12o+02-->CO2+H20

please help if you can does anyone have any hints when balancing equations?

 

[ND]

Why do they all have O's on them? (on the LHS i mean) Aren't they supposed to be haloalkanes?

 

[zeropoint]

Originally posted by mazza_728
Why can i not seem to balance these equations?

CH4O+O2 --> CO2+2H20
C3H8O+O2-->CO2+H20
C4H10O+02-->CO2+H2O
C5H12o+02-->CO2+H20

please help if you can does anyone have any hints when balancing equations?

CH4O + 3/2 O2 --> CO2 + 2H2O
C3H8O + 9/2 O2 --> 3CO2 + 4H20
C4H10O + 6O2 --> 4CO2 + 5H2O
C5H12O + 15/2 O2 --> 5CO2 + 6H2O

Originally posted by ND
Why do they all have O's on them? (on the LHS i mean) Aren't they supposed to be haloalkanes?

No they are all alkanols.

 

[ND]

Sorry i meant to say alkanes...

edit: they're not alcohols, the respective alcohols would be CH3OH, C3H7OH etc..

 

[spice girl]

Cookbook for complete combustion of CaHbOc (a, b, c are given integers)

Equation should be in the form: CaHbOc + xO2 -> yCO2 + zH2O (where x, y, z are integers)

(NB: as there are no halogens and C and O have even valencies, b should be an even number)

Preferably in this order:
1) Balance #C: y = a
2) Balance #H: z = b/2
3) Balance #O: c + 2x =2y + z (or rearranging: x = y + z/2 - c/2)

 

[abdooooo!!!]

Originally posted by mazza_728
please help if you can does anyone have any hints when balancing equations?

balancing is kind of easy... in the case that you described just:

1. check if the number of Cs is the same on both side, if not, times the coefficient (in this case the coefficient of the CO2) by something to equal the Cs on the LHS

2. then check the H and do the same as above but now with water's coefficient (H2O)

3. now check for the O... same as above except with the O2 on the LHS

4. now if you want to get rid off the fractions cancel it off by... you know what to do just like in math

 

[zeropoint]

Originally posted by ND
edit: they're not alcohols, the respective alcohols would be CH3OH, C3H7OH etc..

Actually, they are alcohols. Note that methanol (CH3OH) is equivalent to CH4O. It is simply a notational difference.

 

[ND]

Duh, sorry. All that alcohol during schoolies has fucked my brain...

 

[abdooooo!!!]

schoolies' alcohol = bad

chemistry's alcohol = good