<3 backaye lmao apparently people think
rip there goes ur marks
a lot of people forgot that √k = 1-√h
their area function was (1-√h)² instead of (1-√h)⁴
there goes another mark
bless u janzen choi for being the one person who got my spiky volume correct <3
another kid almost got the answer correct but they forgot to double the result bc they were only finding the upper half volume...
rip in pieces
also a lot of u stoners thought the curved edges were like a square minus a circle????
can u even graphs plz
Hey man, thanks for pointing this out. I've attached a more detailed solution. I got a bit lazy towards the end and also wanted to keep it within 2 pages, but I think this should do the trick. I was supposed to write the Q16 solutions on Sat night but I̶ ̶w̶e̶n̶t̶ ̶t̶o̶ ̶E̶l̶ ̶J̶a̶n̶n̶a̶h̶ ̶a̶n̶d̶ ̶c̶h̶i̶l̶l̶e̶d̶ ̶w̶i̶t̶h̶ ̶m̶a̶t̶e̶s̶ ̶t̶i̶l̶l̶ ̶1̶a̶m̶ ̶i̶n̶s̶t̶e̶a̶d̶ I didn't have time to do them, so this one's on me.I think the Q16h solution is still not quite correct.
Whilst it is true that
x-k\alpha =< x for each x, we cannot simply bound the product of factors of this form by the product of the x's, as some of these terms will in general be negative.
Another way of seeing this problem is that if we take absolute values and k\alpha happens to be close to n, then we see that in fact the early terms in this product are the largest, (but the inequality is still true because the later terms in the product are small).