calculating pH (1 Viewer)

sssona09 · Jan 15, 2018

how would I account for ionisation rate
Calculate the pH of 0.05 mol L-1 citric acid if it has an ionisation rate of 50%

thank you

jathu123 · Jan 15, 2018

$\noindent $Degree of Ionisation $ = \frac{[H^+]}{[HA]}\times 100 \% \\ \\ $Where $ HA $ is the intact acid molecule $ \\ \\ \therefore 0.5 = \frac{[H^+]}{0.05} \Leftrightarrow [H^+]=0.025 \\ \\ $ pH $ = -\log [H^+]\\ = -\log 0.025 \\ = 1.6$

it basically means that only 50% of all acid molecules gets ionised
So if the concentration of the acid is 0.05, you'd expect the concentration of [H+] to be half of that (ie 0.025)
Now plug this into pH formula to find pH

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calculating pH (1 Viewer)

sssona09

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jathu123

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