Calculus question! (1 Viewer)

[yeezus]

Hey, I'm in year 10 right now, so forgive the lack of knowledge

Question 1: The curve y=root(x-3) has a tangent with gradient 1/2 at point N. Find co-ordinates for N
Question 2: The function f(x) =3rootx has f '(x) =3/4 evaluate x

Thanks!

 

[AnimeX]

Hey, I'm in year 10 right now, so forgive the lack of knowledge

Question 1: The curve y=root(x-3) has a tangent with gradient 1/2 at point N. Find co-ordinates for N
Question 2: The function f(x) =3rootx has f '(x) =3/4 evaluate x

Thanks!

Question 1: Differentiate y with respect to x, sub in dy/dx =1/2 and solve for x, then put that point back into y=sqrt[x-3] and you should have N.

Question 2: I'm not 100% sure what this question is asking, possibly it means find x. So, differentiate f(x) and make it equal 3/4, solve for x, should be the answer.

^.^

 

[yeezus]

for question 1 I differentiate y=root(x-3) and get 1/2sqroot(x-3) and when i try sub in gradient = 1/2 I get a math error :L

 

[bedpotato]

for question 1 I differentiate y=root(x-3) and get 1/2sqroot(x-3) and when i try sub in gradient = 1/2 I get a math error :L

What do you mean "sub in gradient". You let y' = 1/2, and solve for x. And then sub in the value of x back into y to find the y coordinate.

 

[yeezus]

What do you mean "sub in gradient". You let y' = 1/2, and solve for x. And then sub in the value of x back into y to find the y coordinate.

Ah! OK it becomes 1/2= 1/2sqroot(x-3) and solve, thanks! didn't see it at first

 

[AnimeX]

Ah! OK it becomes 1/2= 1/2sqroot(x-3) and solve, thanks! didn't see it at first

Yup