#### _caecilius_iucundum_

##### New Member

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- Jul 10, 2019

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**Can anyone help me?**

The first digit of a 6-digit number is 1. This digit 1 is now moved from the first digit position to the end, so it becomes the last digit. The new 6-digit number is now 3 times larger than the original number. What are the last three digits of the original number?

So far I have only managed to expand to and I'm really not sure if I've made a mistake or how to keep going

3(1abcde) =abcde1

300000+30000a+3000b+300c+30d+3e = 100000a+10000b+1000c+100d+10e+1

299999 = 70000a+7000b+700c+70d+ 7e

42857 = 10000a+1000b+100c+10d+e

Please help, any advice is needed,

Cheers