• Want to help us with this year's BoS Trials?
    Let us know before 30 June. See this thread for details
  • Looking for HSC notes and resources?
    Check out our Notes & Resources page

can someone explain how to do this question please!! (1 Viewer)

iheartgeorge

New Member
Joined
Apr 3, 2006
Messages
12
Gender
Female
HSC
2007
Does somebody tell me what steps i need to carry out to answer this please..
The cost of running a car at an average speed of v km/h is given by:
c= 150 + (v squared)/80 cents per hour
Find the average speed, to the nrs km/h at which the cost of a 500km trip is a minimum
 

word.

Member
Joined
Sep 20, 2005
Messages
174
Gender
Male
HSC
2005
cost = (150 + v^2/80) * time

velocity = displacement/time

c = (150 + 500^2/(80t^2))t
c = 150t + 3125/t

dc/dt = 150 - 3125/t^2

stat points occur when dc/dt = 0
i.e. when 3125/t^2 = 150 -> t^2 = 3125/150 = 125/6
t = ~4.56 (t > 0)

d/dt(dc/dt) = 3125/3t^3 > 0 (t > 0) so this is a minimum

when t = 4.56, v = 500/4.56 = 109.65km/h
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top