# Can someone help with this question finding the area of minor segment (1 Viewer)

#### fan96

##### 617 pages
The area of the quadrant is:

$\bg_white A = \pi r^2 \cdot \frac 14$

The area of the triangle inside is:

$\bg_white A = \frac12 bh$

And the area of the minor segment is the area of the quadrant less the area of the triangle.