Firstly, it was moles not molar concentration (unless im stupid and i can't remember)
Secondly, AgNO3 was limiting as you only started with 0.1 moles of both Pb(s) and AgNO3, but they're in the 1:2 ratio, so if you wanted all the Pb(s) to react, you would need to have 0.2 moles of AgNO3, which you don't have. SO, you only use 0.05 moles of Pb(s) and 0.1 moles of AgNO3. As a result all the Silver ions are removed. Therefore at the end you're gonna have 0.05 moles of Pb(s) remaining. The NO3 isn't gonna change as it is a spectator (as mentioned before) and that's gonna have 0.1 moles final for that. The silver solid will be at 0.1 mol and the Pb2+ will be at 0.05 moles.
All of that requires just use of stoichiometrics and just some common sense. I had to use an extra writing booklet for that too cause i accidentally mixed up my answer. It just takes a bit of concentration.