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I am not sure how you construct a conic with it, it came up in fitzpatrick, 32(c), question 8, proving that tangents from a chord of contact lie at right angles, in the worked solutions, and we dunno what a director circle isOriginally posted by George W. Bush
Which conic are you intending to construct?
Do you think it is ok to quote 'because they lie on the director circle' or does it need to be provenOriginally posted by buchanan
For an ellipse E: x<sup>2</sup>/a<sup>2</sup>+y<sup>2</sup>/b<sup>2</sup>=1, the director circle is C: x<sup>2</sup>+y<sup>2</sup>=a<sup>2</sup>+b<sup>2</sup> and it can be shown that if two tangents on E intersect on C, then they are perpendicular to each other.