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Can someone please verify this (1 Viewer)

currysauce

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When doing the pendulum prac...

u graph Period (Squared)/ Length right

dep/independent (by excels definsition)

please!
 

fi_babezy

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uh...... length is on the yaxis- and period squared is on the x axis
 

Jaydels

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fi_babezy said:
uh...... length is on the yaxis- and period squared is on the x axis
Length goes on the x-axis because it is the independent variable, and period squared on the y-axis, because it is dependent on the length
 

jamesy_1988

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currysauce said:
When doing the pendulum prac...

u graph Period (Squared)/ Length right

dep/independent (by excels definsition)

please!
The lenght is the independent variable in this experiment because you are measuring the time not the lenght. I tinhk thats right, well at least thats how i did it. therefore the lenght goes on the x-axis and the period squared goes on the y-axis.

Jamesy
 

currysauce

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thanks people...

so after u work out gradient and u go 4 pi ^2/ [insert gradient here] = g
 

fi_babezy

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acmilan said:
Thats right.
actually no, i read the prac again and it can be done that way or the other...if you do it the opposite way you have to swap the numbers around anyway...

"x- axis- t^2
y-axis length"
that's how it said to label them in the physics contexts book.
 
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