Centripetal force (1 Viewer)

[Premus]

F = (mv^ 2 ) / r

we had to do an experiment...where we tied a mass(cork) to a string and whirled the string in a circular motion. We found the period, radius and mass(cork).
the velocity is ( 2 * pi * r ) / Period

if we had to graph the relationship between
i ) v and r
ii ) v^2 and r
iii) Tension and Acceleration

what sort of graphs do we get and what is their relationship? I think if you graph iii, you get the mass of the cork
also, is tension just the centripetal force? and how do we find acceleration?

thanks !

 

[Xayma]

Tension is equal to the centripetal force. It is the tension that provides the centripetal force.

i) v=2πr/T
Since Im assuming the period will remain constant throughout.

You will have a graph of y=mx (since when there is no radius there is no velocity). Where m is 2π/T, x is radius and y is v.

ii) Suprise suprise you will have a graph of y=kx², where k is 4π²/T², x is radius, y is v²

iii) Ill give you a guess at which formula contains the force and acceleration.
The mass will be the gradient of the line y=mx, where y is tension and x is acceleration ;^)

 

[tigerchenyanhu]

for Qiii

i think the graph for Tension and Acceleration is simply a linear fuction:y=kx
known from newton second law f=ma

 

[Mtirnova]

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