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Chemistry Question. (1 Viewer)

marcquelle

a.k.a. Michael...Hi!
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I don't get how to answer this.

Calculate the mass of iron that will form from 8 x 10^8g of Fe2O3.

this how i start the question

Fe 2x55.85 = 111.7
Oiii3x16.00I= ii48.0
Fe2O3.......i.=159.7
production of Fe=111.7g

then i went 8 x 10^8g of Fe2O3

i. iii 159.7
. . 8 x 10^8 = ?????


then i get stuck can anyone help me please
 

H4rdc0r3

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(8x10^8 / 159.7) x 111.7 = mass of iron in the chemical formula
 
Last edited:

marcquelle

a.k.a. Michael...Hi!
Joined
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Messages
1,490
Location
Jervis Bay, N.S.W.
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HSC
2009
jellybelly59 said:
marcquelle im not sure if it's correct but cant u find the percentage composition of iron in iron oxide and then multiply that by (8 x 10^8) that or use the mass on molar mass formula like H4rdc0r3.
they both work out right in the end thank you guys
 

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