Circular Motion - Help (1 Viewer)

[Jackson18]

A particle of mass 5 kg is whirled around at the end of a string 1m long. It describes a horizontal cirle with 36 rev/min. Find the tension in the string and the angle of inclination of the string with the vertical.

I have a bit of an idea with this question, but not much.
I struggle to set up equations etc.

Any help would be greatly appreciated.
Cheers
Jackson

 

[MyLuv]

let @ be angle of..., T be tension
w = 36*2(pi)/60=1.2(pi) rad/s
Resolve horizontally:
Tsin@= mw2r
but r = lsin@
--> T sin@=mw2lsin@
--> T= 5*(1.2(pi))^2 * 1=71 N
Resovle vertically :
Tcos@=mg
---> cos@= mg/T= 5*9.8/71
--->@=46.36 degree