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Combinatorics Year 11 Question (1 Viewer)

Thread starter zacn
Start date Aug 19, 2020

Z

zacn

New Member

#1

How many ways are there to arrange 10 people around 2 tables, 1 oak and 1 mahogany, with 5 at each table?

C

Canteen

New Member

#2

Choose 5 people to sit at the mahogany then let the rest sit at the oak:
$\binom{10}{5}=252$

C

Canteen

New Member

#3

oops forgot to arrange them around the tables!
That would make it:
$252\times (5-1)!\times(5-1)!=4032$
I think that should be correct.

Z

zacn

New Member

#4

Canteen said:
oops forgot to arrange them around the tables!
That would make it:
$252\times (5-1)!\times(5-1)!=4032$
I think that should be correct.

That's what I got but the answers have some number around 145000

C

Canteen

New Member

#5

Lol. I can't type into my calculator. I did:
$252\times4\times4=4032$
Should be:
$252\times24\times24=145152$
as I had above.

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