Stefano
Sexiest Member
KFunk : Haha - funny!
acmilan: Don't you think my way is faster though ?
acmilan: Don't you think my way is faster though ?
Yup!acmilan said:For a quadratic, yes
ah ok thanks mateStefano said:@ = {-b +/- root.[b<sup>2</sup>-4ac]}/2a (Quadratic Formula)
Therefore, the roots are:
1. {-b + root.[b<sup>2</sup>-4ac]}/2a (@)
2. {-b - root.[b<sup>2</sup>-4ac]}/2a (@-bar)
Understood?
But can I write that? And yeh I need some proofTrev said:Complex conjugate pairs... (Do you need a proof? Because if you do I don't have one )
No problem mate.kadlil said:ah ok thanks mate
afaik, you can quote that complex roots come in conjugate pairs without proof (correct me if im wrong, i didnt do 4 unit). But if you want proof, my post above shows how to do it, as did KFunk's.kadlil said:But can I write that? And yeh I need some proof