H hendo144 New Member Joined Aug 16, 2009 Messages 12 Gender Undisclosed HSC 2010 Nov 21, 2009 #1 given that (1+i)^n =x + iy, where x and y are real and n is an integer. prove that X^2 + y^2=2^n cheers in advance
given that (1+i)^n =x + iy, where x and y are real and n is an integer. prove that X^2 + y^2=2^n cheers in advance
addikaye03 The A-Team Joined Nov 16, 2006 Messages 1,267 Location Albury-Wodonga, NSW Gender Male HSC 2008 Nov 21, 2009 #2 hendo144 said: given that (1+i)^n =x + iy, where x and y are real and n is an integer. prove that X^2 + y^2=2^n cheers in advance Click to expand... yeah as sikhman (great name btw lol) take modulus of both sides: |rt2|^n=rt(x^2+y^2) x^2+y^2=(rt2)^2n x^2+y^2=2^n
hendo144 said: given that (1+i)^n =x + iy, where x and y are real and n is an integer. prove that X^2 + y^2=2^n cheers in advance Click to expand... yeah as sikhman (great name btw lol) take modulus of both sides: |rt2|^n=rt(x^2+y^2) x^2+y^2=(rt2)^2n x^2+y^2=2^n