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Complex Numbers Vector Help (1 Viewer)

AreYouAlright?

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I'm so lost when it comes to questions involving complex numbers and vectors, can someone please explain to me how you get to the statement that Q is z-u in this solution attatched.
 

AreYouAlright?

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But how do you get that statement, how do we know that Q is the complex no (u-v)?
 

Stefano

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AreYouAlright? said:
But how do you get that statement, how do we know that Q is the complex no (u-v)?
With complex vectors it doesn't matter where the 'lines' are. In this case, BA=OQ because they have the same length and are parralel.

So, working with BA:

To get from B to A we must;
1. Go from B to O (-OB)
2. Go from O to A (OA)

Adding these;
OA-OB = u-v

And since OQ = BA;
OQ = u-v


All good? :)
 

.ben

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how do you rotate vectors through non 90 degree angles?
 

Trev

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If you want to lengthen the vector by 3, and rotate the vector 135 degrees (3pi/2) clockwise you would mutliply the vector by 3cis(-3pi/4) for example.
Hope that sorta helps :eek:
 

robbo_145

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multiply by Cisθ where θ is the angle in radians

hence rotation by Π/2 anti clockwise is the multiplication by i
as Cis(Π/2) = i

edit: Trev was too quick :p
 

AreYouAlright?

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Stefano said:
With complex vectors it doesn't matter where the 'lines' are. In this case, BA=OQ because they have the same length and are parralel.

So, working with BA:

To get from B to A we must;
1. Go from B to O (-OB)
2. Go from O to A (OA)

Adding these;
OA-OB = u-v

And since OQ = BA;
OQ = u-v


All good? :)
Thanks heaps that was exactly how i needed to hear it explained... lol it's hard i can only think about maths problems in a certain linear way.
 

Stefano

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AreYouAlright? said:
Thanks heaps that was exactly how i needed to hear it explained... lol it's hard i can only think about maths problems in a certain linear way.
No problem mate! I'm glad i've managed to help someone. Ussually I'm the one asking for help! haha.
 

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