Curve sketching (1 Viewer)

[nottellingu]

Hey guys...i need help on sketching the derivative of a function. Can someone please give me a run down on it. Thank u

 

[Mark576]

Think logically;

- Where f(x) has turning points, f'(x) = 0 and hence cuts the x-axis

- Where f(x) cuts the x-axis, f(x) = 0 and hence f'(x) = 0

- Where f(x) is increasing, f'(x) > 0 and hence above the x-axis

- Where f(x) is decreasing, f'(x) < 0 and therefore below the x-axis

- Where f(x) has a point of horizontal inflection, i.e. f'(x) = 0 and f''(x) = 0, there will be a turning point touching the x-axis

- Where f(x) has a point of inflection, f'(x) = 0, therefore there exists a turning point

Hope that helped

 

[Slidey]

Hey guys...i need help on sketching the derivative of a function. Can someone please give me a run down on it. Thank u

Um. It's the same as sketching any other function.

Do you mean you need help on sketching a function once you've found its derivative?

 

[nottellingu]

I mean lyk when they giv u a picture of a f(x) graph and tell u to sketch f'(x). Thanks for ur help Mark576

 

[Mark576]

I mean lyk when they giv u a picture of a f(x) graph and tell u to sketch f'(x). Thanks for ur help Mark576

Not a problem