Derive f(x) = sqrt(9-x^2) + 4 (1 Viewer)

Prawnchip · May 20, 2013

Using radius and tangent theorems...
Thanks!!

Shazer2 · May 20, 2013

$f(x)=\sqrt { 9-{ x }^{ 2 } } +4\\ \qquad \qquad \qquad =(9-{ x }^{ 2 })^{ \frac { 1 }{ 2 } }+4\\ \\ f'(x)=-x(9-{ x }^{ 2 })^{ -\frac { 1 }{ 2 } }\\ \qquad \qquad \qquad =-\frac { x }{ \sqrt { 9-{ x }^{ 2 } } }$

Is this what you mean?

Prawnchip · May 20, 2013

Yeah kind of

..but is it possible to determine it graphically using gradients and perpendicular lines?

Derive f(x) = sqrt(9-x^2) + 4 (1 Viewer)

Prawnchip

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