Differentiation Question (1 Viewer)

Crosswinds

Member
Joined
Jun 28, 2008
Messages
56
Location
Central Coast
Gender
Female
HSC
2010
Okie, this question's annoying me 'cause i know it's really easy but I can't get the same answer as is in the back of the textbook:

"Find any turning points on the curve y = (4x^2 - 1)^4 and determine their nature."

I worked out that the stationary points are (0, 1), (0.5, 0) and (-0.5, 0), and that the first one of those [(0, 1)] is a maximum turning point. All of which is correct according to the answers. But then I found that the other two were points of inflexion, whereas the answers say (0.5, 0) and (-0.5, 0) are both minimum TPs.

Could someone please explain what I'm doing wrong?? Thanks!
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,144
Gender
Male
HSC
2006
Okie, this question's annoying me 'cause i know it's really easy but I can't get the same answer as is in the back of the textbook:

"Find any turning points on the curve y = (4x^2 - 1)^4 and determine their nature."

I worked out that the stationary points are (0, 1), (0.5, 0) and (-0.5, 0), and that the first one of those [(0, 1)] is a maximum turning point. All of which is correct according to the answers. But then I found that the other two were points of inflexion, whereas the answers say (0.5, 0) and (-0.5, 0) are both minimum TPs.

Could someone please explain what I'm doing wrong?? Thanks!
Remember that you have to check that there is a CHANGE IN SIGN in the second derivative to have an inflexion point.
dy/dx = 32x(4x² - 1)³
d²y/dx² = 32(4x² - 1)³ + 32x(24x)(4x² - 1)²
= 32(4x² - 1)²[4x² - 1 + 24x²]
= 32(4x² - 1)²(28x² - 1)
Since x = ±0.5 makes both dy/dx and d²y/dx² as zero, we can only deduce they horizontal points of inflexion if we test that the signs change on either side of ±0.5. When you try this, it turns out that d²y/dx² DOES NOT change sign, therefore our results are inconclusive. This can happen when you have polynomials of degree 4 or higher.

What you should do is test both sides x = ±0.5 and check the sign of the first derivative (that table thingy). e.g. test x = 0, and x = ± 1. A table of values of dy/dx at those x-values should tell you it's a minimum.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top