drawing f(x) and f'(x) curves (1 Viewer)

[cakes]

When they draw an f(x) curve, and ask you to draw the derivative curve, is there some sort of rule?? And the other way around as well?

Any help would be appreciated

 

[crazylilmonkee]

stationary points of the f(x) would be on the x-axis on the f'(x) curve...
u mean like that?

 

[cakes]

yup...

what else?!?

 

[kimmeh]

this sounds more like 4 unit maths... lol


umm
for f'(x), it has x intercepts at tps..

but if they give u the function, if i were you, i'd differentiate it, then graph it like normal

 

[ND]

Here are some rules:

-a stationary pt on f(x) is a root of f'(x)
-a pt of inflexion on f(x) is a stationary pt on f'(x)
-if the gradient is positive on f(x), f'(x)>0
-if the gradient is negative on f(x), f'(x)<0
-if the gradient is increasing on f(x), the gradient is positive on f'(x)
-if the gradient is decreasing on f(x), the gradient is negative on f'(x)

 

[cakes]

thanks guys!!

 

[SmokedSalmon]

Originally posted by ND
Here are some rules:

-a stationary pt on f(x) is a root of f'(x)
-a pt of inflexion on f(x) is a stationary pt on f'(x)
-if the gradient is positive on f(x), f'(x)>0
-if the gradient is negative on f(x), f'(x)<0
-if the gradient is increasing on f(x), the gradient is positive on f'(x)
-if the gradient is decreasing on f(x), the gradient is negative on f'(x)

phew thanks for that ND. Now I can't make a mistake.

 

[iambored]

Originally posted by ND
Here are some rules:

-a stationary pt on f(x) is a root of f'(x)
-a pt of inflexion on f(x) is a stationary pt on f'(x)
-if the gradient is positive on f(x), f'(x)>0
-if the gradient is negative on f(x), f'(x)<0
-if the gradient is increasing on f(x), the gradient is positive on f'(x)
-if the gradient is decreasing on f(x), the gradient is negative on f'(x)

thanks! i was trying to get a list together but missed some