Dry cell reduction - one electron? (1 Viewer)

[Looking Glass]

Hi,
I was wondering if anybody could locate my error in the following redox equations for the dry cell. I can't figure out why there is supposed to be only one electron in the reduction equation. (I thought one was taken up by the Ammonium ion and another by the Manganese, therefore requiring two). Not that this is a need-to-know kind of thing, but it's causing frustration. I appreciate any help anyone can give.<SUB>
<SUB></SUB>
</SUB><SUB></SUB>
<SUB>Jacaranda;
NH&shy;<SUB>4</SUB><SUP>+ </SUP>+ MnO<SUB>2</SUB> + H<SUB>2</SUB>O + H<SUP>+</SUP> + e<SUP>-</SUP> --> Mn(OH)<SUB>3</SUB> + NH<SUB>3</SUB>
</SUB>
<SUB>Looking Glass;</SUB>
<SUB></SUB>
Zn<SUP>&shy;&shy;</SUP><SUB>&shy;</SUB>&shy;&shy;&shy;&shy;<SUB>&shy;</SUB> ----> Zn<SUP>2+</SUP> + 2e<SUP>-

</SUP>2NH<SUB>4</SUB>Cl + Zn<SUP>2+</SUP> ----> ZnCl<SUB>2</SUB> + 2NH<SUB>4</SUB><SUP>+<?XML:NAMESPACE PREFIX = O /><o></o></SUP>
<SUP><o> </o></SUP>
NH&shy;<SUB>4</SUB><SUP>+ </SUP>+ e<SUP>- </SUP>----> NH<SUB>3 </SUB> + H<SUP>+</SUP>

MnO<SUB>2</SUB> + H<SUB>2</SUB>O + H<SUP>+</SUP> + e<SUP>-</SUP> ----> Mn(OH)<SUB>3<o></o></SUB>
<SUB><o> </o></SUB>
NH&shy;<SUB>4</SUB><SUP>+ </SUP>+ MnO<SUB>2</SUB> + H<SUB>2</SUB>O + H<SUP>+</SUP> + 2e<SUP>-</SUP> ----> Mn(OH)<SUB>3</SUB> + NH<SUB>3</SUB>

 

[Kmahal1990]

Yeah different books/sources have different equations for the dry cell. Where did you get that there is only one electron gained (question, not rhetorical)?

In conquering chemistry book, the reaction of an 'ordinary' dry cell is stated as below:
Zn(s) --> Zn2+(aq) + 2e-

Nh4+(aq) + MnO2(s) + H2O(l) + e- --> Mn(OH)3(s) + NH3(aq)

I wouldn't worry about which equation you write in an exam, asking for the chemical reaction involved in a dry cell. As long as your reaction is balanced, it should be fine.