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that seems correctsarevok said:For 3b), I got a standard deviation of 1307 and a mean of 3673. Can any one confirm this? I dunno, the stdev seems kinda big.
saverok...you always seem to be sleepysarevok said:zzzzzzzzzzzzzzzzzzzz
I think he does that when he wants people to post up more of their answers *hint*ToO LaZy ^* said:saverok...you always seem to be sleepy
why is that the case?..attending murray's lecture yeah?
*hint hint*matt#1 said:I think he does that when he wants people to post up more of their answers *hint*
finally..someone who understands my sarcasm.1Time4thePpl said:No he does that because he's a [.....] Other people are always sharing and trying to maximise their marks. Sarevok contributes when he needs help, and then promptly deletes any posts that he makes with anything that could be useful to us.
i got the same answerressul said:I did in this way:
P(X>2000)=0.9
P(X>6000)=.03
In the other words:
P(X<2000)=0.1
P(X<6000)=0.97
Then
1:2000-u/SD=2.33(Z value from normal table)
2:6000-u/SD=1.88(As above)
Slove 1 and 2, I got u=4213.78; SD=950.12
Any commente?