Engineering Studies 2013 Specimen Examination (1 Viewer)

[vishaal99]

Hey guys, just wondering if anyone could give me a hand with this question in the 2013 Specimen exam paper. I'm usually really good with pictorial drawings, but this one has me really confused :S
All help is appreciated! Thankyou!

 

[Rathaen]

Hard to explain without drawing it out, but it's an angle bracket. Bottom face has a countersunk hole in it and a sort of bevelled or angled edge and is square, and the vertical face has one rounded corner and one square corner, as well as a hole through.

I'll see about drawing it out if I can find some time later today, unless you've already figured it out.

 

[vishaal99]

Hard to explain without drawing it out, but it's an angle bracket. Bottom face has a countersunk hole in it and a sort of bevelled or angled edge and is square, and the vertical face has one rounded corner and one square corner, as well as a hole through.

I'll see about drawing it out if I can find some time later today, unless you've already figured it out.

ahhhh I see! Was wondering what those dashed lines at the bottom were..
That's alright, no need to draw it, you've done enough! It helped plenty
Thankyou!

 

[Tacoo]

Tomorrows the big day

 

[Brotein]

Drawings my worst out of all engineering. Anyone have last minute tips?

 

[Tacoo]

Prepare thy anus.
Also, what answer did you get for question 13 in the multiple choice on the specimen paper?

 

[vishaal99]

Prepare thy anus.
Also, what answer did you get for question 13 in the multiple choice on the specimen paper?

for 13 I got D 300MPa

 

[vishaal99]

Drawings my worst out of all engineering. Anyone have last minute tips?

practice, practice, practice!

 

[Tacoo]

Tell me your method

 

[vishaal99]

Shear Stress= Force/Cross-Sectional Area

therefore: 150x10^3/50x5 (its 50 because the length of the punch is 25, and thats half the length the plate)
=600MPa
then: 600MPa/2 (divided by two because the punch is half the plate as above ^ in brackets)
=300MPa

 

[Tacoo]

Thanks man, I semi understand now, but how do you know its half the length of the plate??

 

[vishaal99]

All good

tbh with you i dont know :L
it looked like it so i just had a guess haha

 

[Tacoo]

Haha, well then, I'm screwed :/

 

[vishaal99]

yeah im on the same boat dude, dont even worry :L

 

[nick487]

anyone know anything about PCD (Pitched circle diameter)? Q16e 2009 HSC has something about it and in the answers i can't seem to understand what they did or if it has anything to do with the PCD:s
i have attached both the question and solution. If anybody can explain the part of the solution on the left, separated to the rest, it would awesome!!

 

[Tacoo]

No idea dude, join the club though. Dw I think uni admissions will be hella lower next year :L

 

[vishaal99]

hahaha true that :L

And i think you uploaded the question twice..

 

[nick487]

oops. i uploaded the solution twice ahahahah

 

[nick487]

btw i have no clue what u did in Q13.
i was taught when u want shear stress, the area in question is the perimeter multiplied by the thickness.
hence, stress = (15x10^3)/(4x0.025x0.005)=300MPa

 

[Tacoo]

^^^^ Makes more sense , goodluck today lads! Remember when answering questions, if your answer sounds logical, you're probably wrong.