equalibrium: how many moles of carbon dioxide in 50ml of soda water? (1 Viewer)

[gaypsych101]

This must be a really simple question for all of you.

-how many moles of carbon dioxide in 50ml of soda water?

how do i do this? since it's in ml and not in grams i'm kinda stuck now..lol
do i have to convert the ml to grams? or whatnot.
it dosen't give you the concentration and it dosen't ask for molarity.

 

[Riviet]

You've got the idea of converting ml to g, it's simply 1ml = 1g or 1L = 1kg. Then use n=m/M to find number of moles.

 

[poopoohead]

Isn't 50ml=50g

actualy i have no idea- don't listen to me, im stupid

why the hell am i even posting???

 

[pLuvia]

It sure is

n=m/M
MW_CO2=(12.01*2(16.00))g/mole=44.01g/mole
n=50/44.01
=1.14mole

 

[gaypsych101]

It sure is

n=m/M
MW_CO2=(12.01*2(16.00))g/mole=44.01g/mole
n=50/44.01
=1.14mole

That's what i did at first, but when i got the answer 1.14mole i thought it was really big (since most of the answers for questions like this is like 0.03-whatnot moles).
So that's the right answer then? because i don't have an answer for it..., (it's a question from a pratical we have to right up...)

 

[pLuvia]

(since most of the answers for questions like this is like 0.03-whatnot moles).

Doesn't have to be so small, can be big or small depends on the question obviously Yep it should be right though

 

[pkc]

You need to know the weight loss of the soda-water sample before you can calculate the answer.

Its a prac, so the results are relevent.

 

[gaypsych101]

i probably should have posted this first....
here's the full question

1- A student decided to decarbonate a soft drink by tirating 50mL soda water with a 0.1M solution of sodium hydroxide solution. The student recorded that 23.5mL of sodium hydroxied was needed to cause a faint pink colour change of an indicator.

a. calculate the number of moles of carbon dioxide present in a sample.

 

[pkc]

moles NaOH= conc x vol
= 0.1M x 0.0235L
=0.00235

Neutralisation Rxn (abbreviated):
2NaOH + CO2 -> Na2CO3 + H2O

So moles CO2 in sample= 0.00235/2
= 0.001175

 

[gaypsych101]

moles NaOH= conc x vol
= 0.1M x 0.0235L
=0.00235

Neutralisation Rxn (abbreviated):
2NaOH + CO2 -> Na2CO3 + H2O

So moles CO2 in sample= 0.00235/2
= 0.001175

hey, thanks abunch, love yall!