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Equating Coefficients (1 Viewer)

DJel

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Question: "By equating the coefficients of (1+x)10 and (1+x)(1+x)9, show that 10C4 = 9C4 + 9C3"

I understand how to get the coefficients of (1+x)10 and from that I can show the relationship using factorial notation. However, I'm unsure what to do with "(1+x)(1+x)9".

Thanks,

DJel.
 
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DJel said:
Question: "By equating the coefficients of (1+x)10 and (1+x)(1+x)9, show that 10C4 = 9C4 + 9C3"

I understand how to get the coefficients of (1+x)10 and from that I can show the relationship using factorial notation. However, I'm unsure what to do with "(1+x)(1+x)9".

Thanks,

DJel.
you expand the rhs binomally aswell
and u get something like this
(10c0+10c1x+...+10c10x^10)=(1+x)(9c0 + 9c1x+ 9c2x^2+.........+ 9c9x9)
then equate the coefficients of x^4
so you get LHS=10c4x^4
and RHS= 1.9c4x^4 + x(9c3x^3)
= 9c4x^4 + 9c3x^4
hence 10c4= 9c4+9c3
 

DJel

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Thanks for that solution.

Also, I am having a bit of trouble with the short way of finding the greatest coefficient. I know how to expand them out and find the greatest coefficient, however, this just wastes time. What would be the quickest way of doing a question like so;

"Find the greatest coefficient of (2x2 - 3/x)11"?

DJel.
 

lyounamu

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DJel said:
Thanks for that solution.

Also, I am having a bit of trouble with the short way of finding the greatest coefficient. I know how to expand them out and find the greatest coefficient, however, this just wastes time. What would be the quickest way of doing a question like so;

"Find the greatest coefficient of (2x2 - 3/x)11"?

DJel.
There is no quickest way, unfortunately. Expansion will be the best way as well.
 

Aerath

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Really? I thought you could use Tr+1 = an-r*br to find Tr+1 and Tr.
Then solve the coeff of Tr+1 / Tr > 1

And after that, sub it in to find the T with the greatest coefficient.
 

lyounamu

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Aerath said:
Really? I thought you could use Tr+1 = an-r*br to find Tr+1 and Tr.
Then solve the coeff of Tr+1 / Tr > 1

And after that, sub it in to find the T with the greatest coefficient.
That's the method he was talking about wasn't it?

I call that expansion method. lol
(because you expand it and simplify to get the right term).
 

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