Ext. maths students. (1 Viewer)

[xsjado]

How are you coping??
I understand it all, but some of the questions are impossible.. but when explained, i can see how it works....

how bout u?

 

[Kujah]

Some questions of Fitzpatrick and Cambridge are just ridiculously hard for me. But I'm coping thoroughly well in MX1.

 

[jemsta]

yeah cambridge just have some ridiculously hard questions, but i thoroughly remember that one of those hard double angle type questions appear exactly the same on the ext 1 paper, so if you can conquer those, youll rip the ext 1 exams apart.
just keep practicing....and if you have any queries ask your teacher or your tutor (if you have one)

 

[Le3sah]

Not so well. Maths isn't my thing...
I can't wait to drop EXT in term 3 =D

 

[independantz]

Doing alright i guess considering that i do little to no study :< hate being lazy lol, but can't help it =/.

 

[undalay]

wat topics are u struggling with ?

 

[cs01001]

Trig Identities ffs

 

[Kujah]

Some questions of Permutations and Combinations...

 

[cs01001]

P and C are bitches, but nevertheless they won't form a big part in the HSC course/exam anyway... I guess?

Anyone care to help me with Trig Identities?

 

[undalay]

what kind of help do you need ?

 

[tommykins]

trigs easy once you do a few practices. make up a few songs or something so you can remember.

maths general people have a few songs ie. twinkle twinkle little star, area is 2 pied r.

but for me, it's simple for trig identities.

1 + cot^2 = cosec^2 - note that they're co.
1 + tan^2 = sec^2 - tan si the reciprical of cot and so is sec to that of cosec.
sin/cos = tan - try to remember SCT [s/c = t]
cos/sin = cot - [CSC]

so on and so forth.

im not struggling, i just dont pay attention enough

 

[S1M0]

Meh, its alright. I don't pay too much attention in class, and i understand the questions 80% of the time. Some of the really hard questions need explaining, but then i understand them very well.

I suppose some decent effort is required to get alright marks in 3-unit.

 

[vulgarfraction]

Trig identities: someone taught me this is in Year 10, it's the most useful thing I've ever learnt (EDIT: trig-wise... ) and I scribble it in pencil whenever I need it:

- draw three lines intersecting like an asterisk, with one horizontal, and the rest 60 degrees from each other
-from top row, label clockwise: sin cos cot cosec sec tan
-write '1' in the middle where the lines intersect

What this means:

-when you get an inverted triangle, sum of squares of top two is square of bottom
-across a line, each function (of x) is the same as the other function (of 90 - x)
-around the hexagon each function is the product of the two on each side
-opposites are reciprocals



Bloody useful. =) And if you have trouble, try working backwards, finding other ways of expression what you need to prove, etc.

 

[undalay]

Trig identities: someone taught me this is in Year 10, it's the most useful thing I've ever learnt (EDIT: trig-wise... ) and I scribble it in pencil whenever I need it:

- draw three lines intersecting like an asterisk, with one horizontal, and the rest 60 degrees from each other
-from top row, label clockwise: sin cos cot cosec sec tan
-write '1' in the middle where the lines intersect

What this means:

-when you get an inverted triangle, sum of squares of top two is square of bottom
-across a line, each function (of x) is the same as the other function (of 90 - x)
-around the hexagon each function is the product of the two on each side
-opposites are reciprocals



Bloody useful. =) And if you have trouble, try working backwards, finding other ways of expression what you need to prove, etc.

could u explain that again / draw us this diagram .

For me i just have sin^2 + cos^2 = 1
and divide this by whatever i need. If i need sec^2 thats 1/cos^2.
So divide the whole thing by cos^2

Tan^2 + 1 = Sec^2

 

[cl3nta]

that diagram does sound good but the best thing in my opinion is to learn the various identities by practise. and i'll say why too..

Say you get a question where you have to prove LHS=RHS
If you've learnt by practising, this becomes easy marks - all you have to do is manipulate it to get the rhs, not rocket science
If you write down the diagram, because of lack of experience and familiarity with the identities, you're more likely to struggle to get the answer and waste VALUEABLE time which is needed on the "long response" maths questions both in prelim and hsc examinations.

That's my word of advice. I'm currently doing 3u mathematics for hsc and just knowing something is better than learning it - if you can see the distinction... goodluck guys

 

[cs01001]

As for now, I just remember Sin^2 + Cos^2 = 1. Then derive the other two from it. I am working to learn it by heart and practice it.

 

[vulgarfraction]

*sigh* should've done that in first place

http://i82.photobucket.com/albums/j269/vulgarfraction/trig.jpg

Trust me, you don't need to memorize anything.

 

[watatank]

could u explain that again / draw us this diagram .

For me i just have sin^2 + cos^2 = 1
and divide this by whatever i need. If i need sec^2 thats 1/cos^2.
So divide the whole thing by cos^2

Tan^2 + 1 = Sec^2

that's how it should be done.

 

[xsjado]

 <img src="http://i82.photobucket.com/albums/j269/vulgarfraction/trig.jpg" />

opposites are recipricals. But what are the other relations?

 

[independantz]

Hey, anyone know what topic we start sketching graphs etc.?