finding TDS (1 Viewer)

sssona09 · Jan 7, 2018

http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2010exams/pdf_doc/2010-hsc-exam-chemistry.pdf

31)a)I)

thank you

captainhelium · Jan 7, 2018

$The solid remaining from the evaporating basin is considered as the TDS. You normally don't include residue from filter paper in TDS calculations I think.$

$Therefore, mass of TDS is 'Mass of evaporating basin' - 'Mass of basin and solid remaining'$

$∴ 44.67 - 43.53 = 1.14 grams$

$To find percentage of TDS, use the mass of TDS over the water sample as a fraction then make it a percentage by multiplying by 100$

$\frac {1.14} {250}$ $x 100$ $= 0.46 \%$

$I hope that's correct!$

N.B - Latex input is still new to me so the layout of my answer may be a bit funny xD

jathu123 · Jan 7, 2018

TDS is found by evaporation to dryness
so the solid remaining in the basic after evaporation is the mass of the TDS, which is 44.67-43.53 = 1.14

now to find the percentage, divide this by 250 mLs and times it by 100
= 0.46% (to 2sf)

finding TDS (1 Viewer)

sssona09

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captainhelium

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jathu123

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