XcarvengerX
Chocobo
It is interesting to see Lazarus posting three posts within 80 minutes. I think edit button has not been implemented then...
npUzurOger said:hmm seems ive completely forgotten about this thanks for the bump fishy
what ?Lazarus said:Yes, both differentiation and integration from first principles are examinable.
Differentiation (example):
..lim.......f(x+h) - f(x)
h -> 0............h
Integration (example):
Integral[sqrt(r^2 - x^2)] between -r and r
Use A = (Pi*r^2)/2.
This is only for definite integrals, and thus to do your question, you would have to split the interval into n such intervals and then find limits of the upper and lower rectangles.To find a definite integral by first principles, dissect the interval into n equal subintervals, construct upper and lower rectangles on each subinterval, and find the sums of the upper and lower rectanlges. Then their common limit till be the value of the integral.