rajeenth said:
sorry ..heres the question
A and B are two towers, B being 4 KM due east of A. The true bearings of a flagpole,C, from A and B are (alpha) east of north and (alpha) west of north respectively. The true bearings of a second flagpole,D, from A and B are ((alpha)+(beta)) east of north and ((alpha)-(beta)) west of north respectively. Draw a sketch to indicate the positions of A, B, C and D. Assuming A,B,C,D are on level ground, and that (alpha)=25 and (Beta)=10, find distance between C and D.
You have to draw the diagram. If you draw it yourself, it will look like 2-dimensional diagrams of 2 triangles with the peaks called C and D.
So when you draw this diagram. Just draw 2 triangles (overlapping in the centre, I will call it E).
Using the sine rule, 4km/sin60 = BE/sin 55
Therefore, BE = 3.78350122...
Now, BE/sin 50 = DE/sin 10
Therefore, DE = BE/sin 50 x sin 10
= 3.78350122.../sin 50 x sin 10
=0.857650099...
Now, DE/sin 55 = CD/sin 60
Therefore, CD = 0.906726387....
Therefore, CD = 0.9067 km (to 4 decimal places).
I am sorry if I explained poorly. However, this question is too diagram-based and you need to be able to visualise how the diagram looks like and from that, you solve the question out. I will try posting my diagram up but my camera is broken :mad1: (I am really sorry). I hope that someone posts his/her diagram up.