• Best of luck to the class of 2025 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here

Fun Maths Questions (1 Viewer)

hyparzero

BOS Male Prostitute
Joined
Sep 10, 2005
Messages
241
Location
Wankersville
Gender
Female
HSC
2006
Found the following questions quite interesting:

1. Find ii where i = root(-1)

2. The number a is randomly selected from the set {0,1,2,3,...,98,99}. The number b is selected from the same set.

What is the probabilty that the number 3a+7b is an 16 digit number?
 
Last edited:

Trev

stix
Joined
Jun 28, 2004
Messages
2,035
Location
Pine Palace, St. Lucia, Brisbane.
Gender
Male
HSC
2005
Just having a go at it, i<sup>i</sup>:
Since e<sup>ix</sup>=cisx, when x=pi; e<sup>i.pi</sup> = -1.
ln[e<sup>i.pi</sup>] = ln[-1]
So i.pi = ln[-1].

Let k=i<sup>i</sup>
k<sup>2</sup>=i<sup>2i</sup>=(-1)<sup>i</sup>
ln[k<sup>2</sup>]=ln[(-1)<sup>i</sup>]
2ln[k]=i.ln[-1], since ln[-1]=i.pi then:
2ln[k]=i.i.pi
k=e<sup>-pi/2</sup>
&there4; i<sup>i</sup>=e<sup>-pi/2</sup>.
Yeah?
 

Bobness

English / Law
Joined
Aug 7, 2005
Messages
1,655
Location
Sligo
Gender
Male
HSC
N/A
I couldn't resist it ...

Maths is not fun

That is all :eek:
 

hyparzero

BOS Male Prostitute
Joined
Sep 10, 2005
Messages
241
Location
Wankersville
Gender
Female
HSC
2006
Trev said:
Just having a go at it, i<sup>i</sup>:
Since e<sup>ix</sup>=cisx, when x=pi; e<sup>i.pi</sup> = -1.
ln[e<sup>i.pi</sup>] = ln[-1]
So i.pi = ln[-1].

Let k=i<sup>i</sup>
k<sup>2</sup>=i<sup>2i</sup>=(-1)<sup>i</sup>
ln[k<sup>2</sup>]=ln[(-1)<sup>i</sup>]
2ln[k]=i.ln[-1], since ln[-1]=i.pi then:
2ln[k]=i.i.pi
k=e<sup>-pi/2</sup>
&there4; i<sup>i</sup>=e<sup>-pi/2</sup>.
Yeah?
Yup absolutely correct. However it seems e<sup>ix</sup>=cisx might have to be be proved using the power series beforehand.

Anyone want to take a shot at the question 2?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top