# Galvanic Cell (1 Viewer)

#### bayan92

##### Member
What did everyone put as the anode and cathode?

##### Banned
umm i not sure i think maybe i put anode was lead and cathode is Pt
i hated this question hopefully i still get 5/7

#### aero135

##### Super Ultimate User!

platinum - cathode

#### annabackwards

##### <3 Prophet 9
Yeha

Anode was Lead and inert platinum as cathode.

#### greekmagician

##### New Member
sik thats wat i got. Wasnt to bad that question, equilibrium question i thought was harder

#### Twickel

##### Member
Please post working on how to calculate the EMF of this cell or the potential whatever its called in chem.

Shit, knew what the anode and cathode were just forgot to write them ( OR I HOPE I DID I CANT REMEMBER), shitI dont think I did, I just wrote the half equation happening,

GOD KILL ME NOW 0/3

crap crap crap crap.

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#### bayan92

##### Member
Was it:

Pb(s) --> etc. 0.13V
Fe3+ + e- --> Fe2+ 0.77V

EMF = 0.9V (doesn't work)

#### annabackwards

##### <3 Prophet 9
Was it:

Pb(s) --> etc. 0.13V
Fe3+ + e- --> Fe2+ 0.77V

EMF = 0.9V (doesn't work)
Yeha.

What do you mean it doesn't work? :/

#### mR sinister

##### Member
Accept for the cathode hald equation you have to times by 2 , to balance it out with the Anode half equation.
And in the net ionic equation the 2 electrons cancel.

however this doesnt change the voltage.

#### pman

##### Banned
Woopsie, just said the elemenmt, not anode/cathode

#### Twickel

##### Member
Oh man look what I did for some reason I added the two different iron equations viltages and added 0.13 and 0.46V, what an idiot, so 0/2 0/3 1/2 1/1

its over for me.

#### kanux

##### Member
shit i forgot to change it in my diagram

#### bayan92

##### Member
Yeha.

What do you mean it doesn't work? :/
LOL dw I thought it had to be EMF > 1 to work but it is actually > 0.

Ignore me

##### Banned
damn sounds like i got this almost completely wrong...
i had a good look at my sheet at the back
saw lead was in the middle of Fe3+ and Fe2+
this is what i did
the potential difference between Pb and Fe3+ was some answer
then because Fe2+ was on top of Pb i found the potential difference here and minused it from my first one... because it was going in the opposite direction therefore opposing.
another thing i was thinking of doing was saying the Fe3+/Pb was greater than the other so i was only gonna use that but instead decided the test was easy up till here and mabe... owell i got anode and cathode

wooo 1000 posts =)

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#### Nuendo

##### Member
shouldn't the overall E (voltage) be <0 since it is undergoing electrolysis (non-spontaneous), therefore, it needs an input of |E|

##### Banned
EDIT: double posted

#### bayan92

##### Member
It was a galvanic cell. No power source.

#### kaz1

##### et tu
shouldn't the overall E (voltage) be <0 since it is undergoing electrolysis (non-spontaneous), therefore, it needs an input of |E|
No, it wasn't electrolysis. Electrolysis isn't even in the core syllabus.

#### Imagination

##### New Member
how did you figure that the lead was the anode and the platinum was the cathod??