Galvanic Cells (1 Viewer)

[randomnessss]

How would I calculate the voltage produced for the galvanic cell in the attached image? Thanks in advance.

 

[mat-thew]

First you need to find which substance is oxidised and which is reduced. To do this look at the potential differences of each reaction, in this case:

Cu²⁺ + 2e^- <---> Cu_(s) E = 0.52 V
or
Fe³⁺ + 3e^- <---> Fe_(s) E = 0.77 V

The substance with the lower potential difference will be the substance to oxidised, in this case copper, thus the half equations become:

Cu_(s) <---> Cu²⁺ + 2e^- E = -0.52 V
and
Fe³⁺ + 3e^- <---> Fe_(s) E = 0.77 V

Therefore, voltage produced
= -0.52 + 0. 77
= 0.25V