Hard differentiation (1 Viewer)

[Bdogz]

whats the derivitive wiht respect to x of ln(y-x) , i think u use implicit differentiation but i dont know how to do it

 

[the-derivative]

Let dy/dx = y'

Therefore the derivative with respect to x of ln (y-x) would be:

 

[tommykins]

-1/ln(y-x)

you treat the y as a constant.

 

[Bdogz]

Let dy/dx = y'

Therefore the derivative with respect to x of ln (y-x) would be:

oh k so wat wud be the derivative with respect to x of this equation : y=x^siny + x

i got 2 this step but im nto sure how much of it is right: dy/dx=(lnx.cosy.dy/dx + siny.1/x).e^sinylnx + 1

 

[tommykins]

is that y = x^siny + x or z= x^siny + x?

if the latter, dz/dx = x^sin(y)*sin(y)/x+1

 

[Bdogz]

is that y = x^siny + x or z= x^siny + x?

if the latter, dz/dx = x^sin(y)*sin(y)/x+1

its a completely different question to the 1st thing i posted on here sorry, so the question is find dy/dx of y=x^siny + x

 

[Pwnage101]

-1/ln(y-x)

you treat the y as a constant.

is that y = x^siny + x or z= x^siny + x?

if the latter, dz/dx = x^sin(y)*sin(y)/x+1

Functions of several vairables is not in the HSC, hence partial derivatives is beyond the scope of the syllabus.

 

[tommykins]

yeah i was curious as to why they had to do it.

not like its hard either lol

 

[Drongoski]

Is it: y = x^{sin y} + x ??

If so, is the answer ??




Edit: corrected: it's cos y not cos x; my typo.

 

[Bdogz]

Is it: y = x^{sin y} + x ??

If so, is the answer ??

on the bottom line in denominator i got cosy instead of cosx, but apart from that i got wat u got, i dont hv the answer on me but once i get it ill notify u thanks

NB i shudve put this in the tertiary forum sorry

 

[-Onlooker-]

Functions of several vairables is not in the HSC, hence partial derivatives is beyond the scope of the syllabus.

You sure?

iirc; one of the hsc papers asked us to differentiate or integrate cos (x - y ). It was in the earlier years.

edit: It might not have asked us directly; might have been in the solutions, I can't remember 100% sorry.

 

[Iruka]

There seems to be quite a bit of confusion of partial differentiation with implicit differentiation in this thread.

Implicit differentiation is in the syllabus; partial differentiation is not.

 

[Bdogz]

Is it: y = x^{sin y} + x ??

If so, is the answer ??




Edit: corrected: it's cos y not cos x; my typo.

This is the answer thanks

 

[jchoi]

How does y = xsin y + x ?? turn into

?

Can someone show me the steps please?