help asap (1 Viewer)

[shady145]

find type of curve and stationary points. my teacher cant help!!

(56x-67x^2)^3 (3^6cos45) +y=o
(sin45)

 

[Timothy.Siu]

change the sin 45 and cos 45 to numbers

 

[Trebla]

lol that looks like the most random equation...

 

[cutemouse]

Well, for a stationary pt y'=0

Where did you get this q from?

 

[alakazimmy]

It's a parabola of some sort with stationary point x-value 28/67.
I don't quite get your notation

 

[cyl123]

It's a parabola of some sort with stationary point x-value 28/67.
I don't quite get your notation

No its not a parabola. The degree of equation is 6. So is a polynomial of degree 6 with horizontal points of inflexions at (0,0) and (56/67,0) with stat point (absolute minimum) at x value 28/67.

Its just a more complicated 2U question.

 

[alakazimmy]

beats me. lol