ok heres the question:
- a student placed a 0.5g strip of magnesium ribbon in 100 mL of:
i) o.1 mol/L ethanoic acid
ii) 0.1 mol/L sulfuric acid
Compare the chemistry of the above two reactions in terms of the strength of the acid, rate of reaction and volume of gas formed. Use equations in your answer.
equations:
ethanoic acid + magnesium --> magnesium ethanoate + hydrogen gas
2CH3C00H + Mg --> Mg(CH3C00)2 + H2
Ok, so for volume of gas formed, do i jus find n (m/molecular mass)
and since, no of moles of magnesium = no of moles of hydrogen gas, i then stick it in n=CV, where C = 0.1?
and so similarly for sulfuric acid....
H2S04 + Mg ---> MgS04 + H2
i don't understand how i'm supposed to answer the strength of the acid and rate of reaction part of the question (obviously a solution of sulfuric acid is stronger ie, has a lower pH, compared to a solution of ethanoic acid of the same concentration, as sulfuric acid ionises completly when mixed ith water... is that it?)
whats this rate of reaction busso?
- a student placed a 0.5g strip of magnesium ribbon in 100 mL of:
i) o.1 mol/L ethanoic acid
ii) 0.1 mol/L sulfuric acid
Compare the chemistry of the above two reactions in terms of the strength of the acid, rate of reaction and volume of gas formed. Use equations in your answer.
equations:
ethanoic acid + magnesium --> magnesium ethanoate + hydrogen gas
2CH3C00H + Mg --> Mg(CH3C00)2 + H2
Ok, so for volume of gas formed, do i jus find n (m/molecular mass)
and since, no of moles of magnesium = no of moles of hydrogen gas, i then stick it in n=CV, where C = 0.1?
and so similarly for sulfuric acid....
H2S04 + Mg ---> MgS04 + H2
i don't understand how i'm supposed to answer the strength of the acid and rate of reaction part of the question (obviously a solution of sulfuric acid is stronger ie, has a lower pH, compared to a solution of ethanoic acid of the same concentration, as sulfuric acid ionises completly when mixed ith water... is that it?)
whats this rate of reaction busso?