Help!!! HSC 2006 Q.18 ... Solution need it . plzzz (1 Viewer)

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Skip straight to Part 2 if you don't need to see how the change in gravitational potential energy was derived.
All units are SI units i.e. distance is all in metres and energy is in joules.


Part 1 - The derivation for the gravitational potential energy.

F - final
I - initial

ΔEP = - GmM/rF - (- GmM/rI)
ΔEP = - GmM/rF + GmM/rI
ΔEP = GmM/rI + GmM/rF (Switch signs)
ΔEP = GmM (1/rI - 1/rF) (Factorisation)



Part 2 - Finding GmM from the work done to move an object from 10,000,000 m to 20,000,000 m given the work required is 1.0 MJ

NOTE:
Avoid substituting 6 x 1024 kg into M for the planet as the question did not state the planet was Earth.

ΔEP = GmM (1/rI - 1/rF)
10,000,000 = GmM (1/10,000,000 - 1/20,000,000)
GmM = 10,000,000 / (1/10,000,000 - 1/20,000,000)
GmM = 2 x 1013



Part 3 - Using GmM to calculate work done to move object from 20,000,000 m to 80,000,000 m

ΔEP = GmM (1/rI - 1/rF)
ΔEP = 2 x 1013 (1/20,000,000 - 1/80,000,000)

ΔEP = 750,000 J
 

GG-Legit

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Thanx for the solution mate:

but ,

i think you misread the question:

For Part 2:its suppose to be
Finding GmM from the work done to move an object from "centre of the planet" m to 20,000,000 m given the work required is 1.0 MJ


For Part 3 :its suppose to be
Using GmM to calculate work done to move object from "Centre of the planet"m to 80,000,000 m

and btw: MG = 10^6 J


You should check it ..
 

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GG-Legit said:
Thanx for the solution mate:

but ,

i think you misread the question:

For Part 2:its suppose to be
Finding GmM from the work done to move an object from "centre of the planet" m to 20,000,000 m given the work required is 1.0 MJ


For Part 3 :its suppose to be
Using GmM to calculate work done to move object from "Centre of the planet"m to 80,000,000 m

and btw: MG = 10^6 J


You should check it ..
Yeah, just modify my working by replacing my values with your own.
It happens to me quite often.
 

GG-Legit

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Forbidden. said:
Yeah, just modify my working by replacing my values with your own.
It happens to me quite often.


But doesnt the vaue going to be zero when you are calculating it from planet.

thanx .... that will do ..

just wanted to check answer with you
 

kooltrainer

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Forbidden. said:
Skip straight to Part 2 if you don't need to see how the change in gravitational potential energy was derived.
All units are SI units i.e. distance is all in metres and energy is in joules.


Part 1 - The derivation for the gravitational potential energy.

F - final
I - initial

ΔEP = - GmM/rF - (- GmM/rI)
ΔEP = - GmM/rF + GmM/rI
ΔEP = GmM/rI + GmM/rF (Switch signs)
ΔEP = GmM (1/rI - 1/rF) (Factorisation)




how did the plus sign change to minus sign from ur last step?
 

xiao1985

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3rd last step -> 2nd last step was the mistake.... last step was correct.
 

Mark576

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xiao1985 said:
3rd last step -> 2nd last step was the mistake.... last step was correct.
Yeah xiao I knew that, perhaps I should of said 'it was due to a mistake'.
 

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