help = integration problem! (2 Viewers)

[asb_92]

hey guys
ive gotta mental blank...
how do u integrate:

1/(3-x)^2

thanks heaps for the help!!
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[cutemouse]

Integral is: sin^-1(x/sqrt(3)) + c

EDIT: Wrong answer.. whoops =P

 

[Fortify]

if its: 1/(3-x^2)

1/sqrt3 tan^-1 (x/sqrt3) + c

 

[lychnobity]

Hang on a minute... isn't it 1/(3 - x) + C ??

 

[asb_92]

ooo ok
thanks heaps!!
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[Fortify]

asb92, do you mean:

1/(3-x)^2

or

1/(3-x^2) ?

 

[kwabon]

hey guys
ive gotta mental blank...
how do u integrate:

1/(3-x)^2

thanks heaps for the help!!
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integral of (3-X)^(-2)
[ (3-X)^(-1)/(-1 * -1) ]
therefore = 1/(3-X) + c

 

[Fortify]

If it's 1/(3-x)^2

Then the answer is 1/(3-x) + C

 

[lychnobity]

For the integral to be an inverse sign, the question would need a square root sign over the whole of the denominator...

 

[kwabon]

asb92, do you mean:

1/(3-x)^2

or

1/(3-x^2) ?

i srsly dont see how you got sine inverse, even if it was 1/(3-x^2), how is that a sine inverse???
i am pretty sure thats 4 unit and u will have to use partial fractions.

 

[kwabon]

For the integral to be an inverse sign, the question would need a square root sign over the whole of the denominator...

ahaha beat me to it.

 

[Fortify]

i srsly dont see how you got sine inverse, even if it was 1/(3-x^2), how is that a sine inverse???
i am pretty sure thats 4 unit and u will have to use partial fractions.

sorry DAI LO .

I misread it ok ? chill cuz, im not a robot, i make mistakes ok ?

If its 1/(3-x^2)

then its

1/sqrt3 tan^-1 (x/sqrt3) + c

 

[tommykins]

lol the fuck sin inverse

 

[cutemouse]

Sorry, I misread the question... Disregard my answer =)

 

[Timothy.Siu]

sorry DAI LO .

I misread it ok ? chill cuz, im not a robot, i make mistakes ok ?

If its 1/(3-x^2)

then its

1/sqrt3 tan^-1 (x/sqrt3) + c

no, tan inverse is it its positive...what are u doing.

 

[kwabon]

no, tan inverse is it its positive...what are u doing.

LOL, omg, i think its time for fortify to go over his/her extension notes.

 

[kwabon]

sorry DAI LO .

I misread it ok ? chill cuz, im not a robot, i make mistakes ok ?

If its 1/(3-x^2)

then its

1/sqrt3 tan^-1 (x/sqrt3) + c

and does my reply really sound that arrogant. if so sorry....

 

[tommykins]

no, tan inverse is it its positive...what are u doing.

He is correct, although my maple tells me its arctanh

 

[Fortify]

and does my reply really sound that arrogant. if so sorry....

Sorry man, I wasn't in the mood before. I feeling better now. I was distracted by something else on my mind.

 

[asb_92]

lol im confused... :S

umm its 1/(3-x)^2


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