Help: Projectile motion (1 Viewer)

[Harkaraj]

Could anyone help me with proving the following:

Two particles P1 and P2 are projected simultaneously from the points A and B, where AB is horizontal. The motion takes place in the vertical plane through A and B. The initial velocity of P1 is V1 at an angle theta1 to the horizontal, and the initial velocity of P2 is V2 at an angle theta2 to the horiztonal. You may assume that the equations of motion of a particle projected with velocity V at an angle theta to the horizontal are x=Vtcostheta and y=-1/2 gt^2 + Vtsintheta.

Show that the condition for the particles to collide is V1sintheta1 = V2sintheta2.

This is question 13, chapter 3G in cambridge yr 12 3u maths

Thanks

 

[ssglain]

As with any question, the first step is to translate that chunk of English text into a mathematical relation. In this case, we are after the condition for collision. Think about what "collision" implies about the position of the two particles in terms of the mathematical description of their motion.

The solution has been attached.

 

[Harkaraj]

Thanks alot