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help wanted with math Q (1 Viewer)

frankenstein

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I have a test tommrrow morining and i need HELP!

so can some one please give me an explanation and answer to the folowing question? =]


What values can a take in these expressions?


sq rt a - 4 = 0

Its a parabola question...so please gimme sum explanation to this.:headbang:
 

frankenstein

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this question can be viewd in the new signpost math text book, page 323, q3-a.

i await yo help!
 

z600

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[FONT=宋体][FONT=宋体][FONT=宋体]I dont see how it's a quadratic equation, whether the
[FONT=宋体]√ includes the (a-4) or not . I graph both cases on a graph calculator, looks nothing like a parabola. [/FONT]
[/FONT][FONT=宋体][/FONT]
[/FONT][/FONT]
 

xlr8-crillz

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SoulSearcher said:
Bump up the thread for that comment?
didnt plan on that

z600 said:
[FONT=宋体][FONT=宋体][FONT=宋体]I dont see how it's a quadratic equation, whether the
[FONT=宋体]√ includes the (a-4) or not . I graph both cases on a graph calculator, looks nothing like a parabola. [/FONT]
[/FONT]
[/FONT][/FONT]
What does it look like??:confused:

I seriously dont know!
 
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Riviet

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It's half a parabola. :p

Replace "a" with "x" and turn it into a cartesian equation:

y=sqrt(x-4)

This is a half of a sideways parabola, the half taken is the upper one because that half has all the positive y-values.

Justification that it's a sideways parabola:
y2=x-4 (squaring both sides)
x=y2+4

To sketch this:
Graph y=x2+4 in pencil.
x=y2+4 is a reflection of y=x2+4 in the line y=x (inverse function) - sketch this inverse function.
Since y can only be positive in y=sqrt(x-4), rub out the bottom half of your sideways parabola. This leaves you with the sideways half parabola.
 

xlr8-crillz

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Riviet said:
It's half a parabola. :p

Replace "a" with "x" and turn it into a cartesian equation:

y=sqrt(x-4)

This is a half of a sideways parabola, the half taken is the upper one because that half has all the positive y-values.

Justification that it's a sideways parabola:
y2=x-4 (squaring both sides)
x=y2+4

To sketch this:
Graph y=x2+4 in pencil.
x=y2+4 is a reflection of y=x2+4 in the line y=x (inverse function) - sketch this inverse function.
Since y can only be positive in y=sqrt(x-4), rub out the bottom half of your sideways parabola. This leaves you with the sideways half parabola.
You Genius!!

yeh i get it now after u put it into y=sqrt(x-4), but is this how you would figure out all equations with different values, e.g. the one above where u just replace the pronumeral with x and solve.
 
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Aerath

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LOL - taking a stroll down memory lane? ;)
 

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