help with this Q plz (1 Viewer)

[hatty]

how do u differentiate 3^x?

i know its 3^xLnx

but can someone please explain to me how so?

thanks

 

[KeypadSDM]

3^x
= e^Ln[3^x]
= e^[xLn[3]]

The rest follows from there.

d/dx 3^x = Ln[3] * e^[xLn[3]]
= Ln[3] * 3^x

 

[hatty]

you legend

 

[Grey Council]

lol, well put. Its a good description, innit?

*sigh* wish I get 100 in ext 1 maths, and 99 in ext 2 maths.