MedVision ad

Help with trig question (1 Viewer)

pikachu975

Premium Member
Joined
May 31, 2015
Messages
2,739
Location
NSW
Gender
Male
HSC
2017
2cos^2 (3a) - 1 = cos6a from the identity cos2x = 2cos^2 x - 1
 

jazz519

Moderator
Moderator
Joined
Feb 25, 2015
Messages
1,955
Location
Sydney
Gender
Male
HSC
2016
Uni Grad
2021
Remember that cos2x=2cos^2(x)-1

So the thing simplifies to cos6alpha
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top