How do I apply KCL here? (1 Viewer)

StudyOnly

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Did you get an answer yet? I got 1200ohms for R2, then using V=IR I got I = 36/1200 = 0.03A. I am fairly sure it is correct since if I add it with the current from the 400ohm resistor I get 120mA. I'll explain it further if it is confirmed correct or if you want a further explanation.
 

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