how do i differentiate the following, simple! (1 Viewer)

[girlworld_club]

y = 5 / (x-3)

I was thinking of moving the (x-3) to the top so it become (x-3)^-1

and then use y = u~v + v~u

can someplace please help me.. thanks
please show full working.

 

[anwar1506]

You can use the quotient rule. y'= (u'v - uv')/ v^2

Therefore, y'= 0(x-3) - 1(5) / (x-3)^2
∆ y'= -5/(x-3)^2

 

[soloooooo]

You are correct in moving it to the numerator like that; then just carry out differentiation normally.

 

[Demise]

y= 5 / (x-3) -> 5 . (x-3)^-1
y' = -5 . (x-3)^-2
y' = -5 / (x-3)^2

Guy above already beat me.

 

[Peeik]

The quickest way is using the chain rule. See below.

 

[soloooooo]

Damn my basic mathematics has got bad.