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How do u derive the displacement formula? (1 Viewer)
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hatty
Banned
the derivative of ut = u (because u is a constant)
the derivative of 1/2at^2 = at
( the power 2 is taken down and is multiplied by the 1/2, hence the 2's cancel out, making it just 1, at remains, and you minus 1 fromt the power 2, hence you are only left with at)
:.
the velocity = u + at.
Q.E.D
how good am i?
i dont even do physics
the derivative of 1/2at^2 = at
( the power 2 is taken down and is multiplied by the 1/2, hence the 2's cancel out, making it just 1, at remains, and you minus 1 fromt the power 2, hence you are only left with at)
:.
the velocity = u + at.
Q.E.D
how good am i?
i dont even do physics
Last edited:
hatty
Banned
qed = quod erat demonstrandum
abdooooo!!!
Banned
well, can't you just visualize this in your head... its pretty simple.
if you want to derive it algebraicly here:
r = vt [since average v = r/t]
= t * (u + v)/2 [since average v = (u + v)/2]
= (ut + vt)/2
= ut + 1/2(vt - ut)
= ut + 1/2(at^2) [since a = (v - u)/t]
if you want to derive it algebraicly here:
r = vt [since average v = r/t]
= t * (u + v)/2 [since average v = (u + v)/2]
= (ut + vt)/2
= ut + 1/2(vt - ut)
= ut + 1/2(at^2) [since a = (v - u)/t]
abdooooo!!!
Banned
just think in your head that the average acceleration will be half the difference between its original velocity and final velocity reached. if you can understand that they the formula should be self explanatory.
This is where ext 1 maths come in handy.
S = ut + at is the same as x = vtcos@(vcos@= u, acceleration in the x direction = 0) and y = vtsin@(vsin@= u) - gt( -g = a). Pick up an ext 1 maths text and read the proofs, theyre all derived through integration.
S = ut + at is the same as x = vtcos@(vcos@= u, acceleration in the x direction = 0) and y = vtsin@(vsin@= u) - gt( -g = a). Pick up an ext 1 maths text and read the proofs, theyre all derived through integration.
freaking_out
Saddam's new life
prolly copied it from a textbook.
abdooooo!!!
Banned
what did you not get in the first place... i don't get that... its so simple lol
of course he/she did... i mean its not like you just make up such a thing called differential calculus in your head while the human race took thousands of years to develop the theory through knowledge over generation with books.Originally posted by freaking_out
prolly copied it from a textbook.
hatty
Banned
be honest
who was the most useful source of help?
abdooooo!!!
Banned
lol@ hatty. mate i derived it algebraicly which is what the dude wanted... so i must be the most help right?