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how do u work this out? (1 Viewer)
- Thread starter ta1g
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Dreamerish*~
Love Addict - Nakashima
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- Jan 16, 2005
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- HSC
- 2005
CuO + 2HCl → CuCl2 + H2O
n = m/M
n = 8/(63.6 + 16)
= 0.1
The molar ratio of CuO to HCl is 1:2.
Therefore 2 x 0.1 = 0.2 moles of HCl is needed to react completely with 0.1 moles of CuO.
The concentration of HCl is 2 mol L-1. This means 0.2/2 L is needed.
0.2/2 = 0.1
. : 0.1 L of HCl is required.
n = m/M
n = 8/(63.6 + 16)
= 0.1
The molar ratio of CuO to HCl is 1:2.
Therefore 2 x 0.1 = 0.2 moles of HCl is needed to react completely with 0.1 moles of CuO.
The concentration of HCl is 2 mol L-1. This means 0.2/2 L is needed.
0.2/2 = 0.1
. : 0.1 L of HCl is required.