Silly Sausage
Well-Known Member
- Joined
- Dec 8, 2014
- Messages
- 594
- Gender
- Male
- HSC
- 2014
Just let the triangle be called
; semi-circle with Domain
be called
and the semi-circle with Domain
called
.
Let
where:
(2)=4)
^{2}\pi}{2})
^{2}\pi}{2})
Thus,\, dx=\int^{5}_{-3}A+B+C\, dx)
^{2}\pi}{2}+\frac{(1)^{2}\pi}{2}=4)
For area, since it can't be negative:
 dx=\int^{5}_{-3}A+|B|+C\, dx)
^{2}\pi}{2}|+\frac{(1)^{2}\pi}{2}=4+\pi)
Let
Thus,
For area, since it can't be negative: