How to find asymptote for tan (1 Viewer)

[Menomaths]

Say I am told to sketch a graph for y = tan (x-pi/4) 0<x<2pi, how would I know what kind of increments I should use for my x axis, and how would I find out the asymptote? Is trial and error the only way?

 

[Menomaths]

Oh my god my post gets cut off again... just click reply with quote to see the question...I hope this message doesn't get cut off too.

 

[chris_power_96]

The whole graph gets shifted by pi/4 to the right. So the asymptotes are just pi/2 +pi/4, 3pi/2 + pi/4 etc for all the asymptotes

 

[Carrotsticks]

To find asymptotes in general, note that the inside of tan(X) CANNOT be equal to either pi/2 or 3pi/2, or any related angles such as -pi/2, -3pi/2, -5pi/2 etc etc.

So let the inside of the bracket (in this case, x-pi/4) be equal to pi/2 and 3pi/2, then solve for x.

 

[anomalousdecay]

The original asymptotes for tanx are at -pi/2, pi/2, 3pi/2, etc.

y = tan(x-pi/4)

let: x-pi/4 = pi/2 (the asymptote value)

x= 3pi/4 is an asymptote.

To sketch the graph, just draw y=tanx but start it at pi/4 instead of at zero (origin).

Hope this helps.

 

[Menomaths]

Oh yeah, thanks for the help guys